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Power is the amount of transferred or converted per unit time. In the International System of Units, the unit of power is the , equal to one per second. Power is a scalar quantity.

Specifying power in particular systems may require attention to other quantities; for example, the power involved in moving a ground vehicle is the product of the plus traction force on the wheels, and the of the vehicle. The output power of a is the product of the that the motor generates and the of its output shaft. Likewise, the power dissipated in an electrical element of a circuit is the product of the flowing through the element and of the across the element.Chapter 13, § 3, pp 13-2,3 The Feynman Lectures on Physics Volume I, 1963


Definition
Power is the rate with respect to time at which work is done or, more generally, the rate of change of total mechanical energy. It is given by: P = \frac{dE}{dt}, where is power, is the total mechanical energy (sum of kinetic and potential energy), and is time.

For cases where only work is considered, power is also expressed as: P = \frac{dW}{dt}, where is the work done on the system. However, in systems where potential energy changes without explicit work being done (e.g., changing fields or conservative forces), the total energy definition is more general.

We will now show that the mechanical power generated by a force F on a body moving at the velocity v can be expressed as the product: P = \frac{dW}{dt} = \mathbf{F} \cdot \mathbf {v}

If a constant force F is applied throughout a x, the work done is defined as W = \mathbf{F} \cdot \mathbf{x}. In this case, power can be written as: P = \frac{dW}{dt} = \frac{d}{dt} \left(\mathbf{F} \cdot \mathbf{x}\right) = \mathbf{F}\cdot \frac{d\mathbf{x}}{dt} = \mathbf{F} \cdot \mathbf {v}.

If instead the force is variable over a three-dimensional curve C, then the work is expressed in terms of the line integral: W = \int_C \mathbf{F} \cdot d\mathbf {r}

 = \int_{\Delta t} \mathbf{F} \cdot \frac{d\mathbf {r}}{dt} \  dt
 = \int_{\Delta t} \mathbf{F} \cdot \mathbf {v} \, dt.
     

From the fundamental theorem of calculus, we know that P = \frac{dW}{dt} = \frac{d}{dt} \int_{\Delta t} \mathbf{F} \cdot \mathbf {v} \, dt = \mathbf{F} \cdot \mathbf {v}. Hence the formula is valid for any general situation.

In older works, power is sometimes called activity.


Units
The dimension of power is energy divided by time. In the International System of Units (SI), the unit of power is the (W), which is equal to one per second. Other common and traditional measures are (hp), comparing to the power of a horse; one mechanical horsepower equals about 745.7 watts. Other units of power include per second (erg/s), per minute, , a logarithmic measure relative to a reference of 1 milliwatt, per hour, per hour (BTU/h), and tons of refrigeration.


Average power and instantaneous power
As a simple example, burning one kilogram of releases more energy than detonating a kilogram of ,Burning coal produces around 15-30 per kilogram, while detonating TNT produces about 4.7 megajoules per kilogram. For the coal value, see For the TNT value, see the article . Neither value includes the weight of oxygen from the air used during combustion. but because the TNT reaction releases energy more quickly, it delivers more power than the coal. If is the amount of performed during a period of of duration , the average power over that period is given by the formula P_\mathrm{avg} = \frac{\Delta W}{\Delta t}. It is the average amount of work done or energy converted per unit of time. Average power is often called "power" when the context makes it clear.

Instantaneous power is the limiting value of the average power as the time interval approaches zero. P = \lim_{\Delta t \to 0} P_\mathrm{avg} = \lim_{\Delta t \to 0} \frac{\Delta W}{\Delta t} = \frac{dW}{dt}.

When power is constant, the amount of work performed in time period can be calculated as W = Pt.

In the context of energy conversion, it is more customary to use the symbol rather than .


Mechanical power
Power in mechanical systems is the combination of forces and movement. In particular, power is the product of a force on an object and the object's velocity, or the product of a torque on a shaft and the shaft's angular velocity.

Mechanical power is also described as the time of work. In , the done by a force on an object that travels along a curve is given by the : W_C = \int_C \mathbf{F} \cdot \mathbf{v} \, dt = \int_C \mathbf{F} \cdot d\mathbf{x}, where defines the path and is the velocity along this path.

If the force is derivable from a potential (conservative), then applying the (and remembering that force is the negative of the of the potential energy) yields: W_C = U(A) - U(B), where and are the beginning and end of the path along which the work was done.

The power at any point along the curve is the time derivative: P(t) = \frac{dW}{dt} = \mathbf{F} \cdot \mathbf{v} = -\frac{dU}{dt}.

In one dimension, this can be simplified to: P(t) = F \cdot v.

In rotational systems, power is the product of the and , P(t) = \boldsymbol{\tau} \cdot \boldsymbol{\omega}, where is angular frequency, measured in radians per second. The \cdot represents .

In fluid power systems such as actuators, power is given by P(t) = pQ, where is in pascals or N/m2, and is volumetric flow rate in m3/s in SI units.


Mechanical advantage
If a mechanical system has no losses, then the input power must equal the output power. This provides a simple formula for the mechanical advantage of the system.

Let the input power to a device be a force acting on a point that moves with velocity and the output power be a force acts on a point that moves with velocity . If there are no losses in the system, then P = F_\text{B} v_\text{B} = F_\text{A} v_\text{A}, and the mechanical advantage of the system (output force per input force) is given by \mathrm{MA} = \frac{F_\text{B}}{F_\text{A}} = \frac{v_\text{A}}{v_\text{B}}.

The similar relationship is obtained for rotating systems, where and are the torque and angular velocity of the input and and are the torque and angular velocity of the output. If there are no losses in the system, then P = T_\text{A} \omega_\text{A} = T_\text{B} \omega_\text{B}, which yields the mechanical advantage \mathrm{MA} = \frac{T_\text{B}}{T_\text{A}} = \frac{\omega_\text{A}}{\omega_\text{B}}.

These relations are important because they define the maximum performance of a device in terms of determined by its physical dimensions. See for example .


Electrical power
The instantaneous electrical power P delivered to a component is given by P(t) = I(t) \cdot V(t), where
  • P(t) is the instantaneous power, measured in ( per ),
  • V(t) is the (or voltage drop) across the component, measured in , and
  • I(t) is the through it, measured in .

If the component is a with time-invariant to ratio, then: P = I \cdot V = I^2 \cdot R = \frac{V^2}{R}, where R = \frac{V}{I} is the electrical resistance, measured in .


Peak power and duty cycle
In the case of a periodic signal s(t) of period T, like a train of identical pulses, the instantaneous power p(t) = |s(t)|^2 is also a periodic function of period T. The peak power is simply defined by: P_0 = \max p(t).

The peak power is not always readily measurable, however, and the measurement of the average power P_\mathrm{avg} is more commonly performed by an instrument. If one defines the energy per pulse as \varepsilon_\mathrm{pulse} = \int_0^T p(t) \, dt then the average power is P_\mathrm{avg} = \frac{1}{T} \int_0^T p(t) \, dt = \frac{\varepsilon_\mathrm{pulse}}{T}.

One may define the pulse length \tau such that P_0\tau = \varepsilon_\mathrm{pulse} so that the ratios \frac{P_\mathrm{avg}}{P_0} = \frac{\tau}{T} are equal. These ratios are called the duty cycle of the pulse train.


Radiant power
Power is related to intensity at a radius r; the power emitted by a source can be written as: P(r) = I(4\pi r^2).


See also

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